NECO Physics (OBJ & Essay) Questions and Answers 2026
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Objective Answers (OBJ)
Essay & Theory Answers
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*PHYSICS OBJ* 1-10: B, A, B, D, E, D, C, C, E, E 11-20: D, E, E, C, A, C, C, C, C, C 21-30: B, C, D, C, B, A, C, D, E, A 31-40: A, C, B, B, A, E, C, E, A, D 41-50: C, E, C, C, D, C, A, D, C, D 51-60: E, E, E, D, B, A, A, A, E, C USE THIS IF URS IS RESHUFFLED ❤️ 🔥 👇🏻👇🏻 1. B – S.I. units: kg, m, s (kilogram, metre, second) 2. A – Frictional force does NOT depend on area of surfaces in contact 3. B – Car descending a hill at constant speed is not accelerating 4. D – Temperature is a scalar quantity (magnitude only) 5. E – Weight loss in water is due to upthrust (buoyant force) 6. D – Gas thermometer is more accurate and gives consistent readings (I and II only) 7. C – Electroscope detects and tests electric charges 8. C – Sound waves are longitudinal, not transverse 9. E – Curved mirrors used for shaving, telescopes, and driving mirrors (I, II and III) 10. E – Force fields exist around magnets and are represented by lines of force (II and III only) 11. D – Shape of earth causes variation in weight of objects 12. E – To measure voltage, connect high resistance wire in series with galvanometer 13. B – Kerosene rises due to cohesion and adhesion 14. C – Atom becomes ionized when electron is completely removed 15. B – Material to be deposited is made the cathode 16. C – A machine does NOT reduce time spent; it reduces effort 17. C – Kainji dam is mainly used for power generation 18. C – Nose cone is a component of a rocket 19. C – Rockets and satellites are used for scientific research 20. C – Total time of flight for maximum range = 1.41u/g 21. B – Period T ∝ √L. Length ×4 → Period ×2 → 2t 22. C – Nuclear, coal and natural gas are non-renewable 23. D – Reducing pressure lowers boiling point and increases evaporation 24. C – Between A and B there are 3 wavelengths 25. B – Increasing wavelength: gamma rays → x-rays → visible light 26. A – Q = F/(BV sinθ) (Option missing B in denominator) 27. C – Both permanent magnets and electromagnets have force fields around them 28. D – R = (XL – XC)/tanφ 29. E – Solids vibrate about fixed positions, not move in straight line 30. A – Viscosity of oil and grease decreases as temperature increases https://whatsapp.com/channel/0029VbDSe3mKbYMO5ZgWbs0i https://t.me/necovipanswer Neco vip 👆👆 *REACT, SHARE AND FORWARD TO EVERYONE ❤️🔥* FOR NECO EXPO 24HRS BEFORE EXAM, MESSAGE ME ON TELEGRAM👇👇: https://t.me/Officialkingjay1 JOIN OUR VIP CHANNEL 👇🏻👇🏻 https://t.me/allexamexporunz ALL STATES(TYPES) QUESTIONS 👇👇 https://t.me/freewassceditto JOIN OUR VIP CHANNEL 👇🏻👇🏻 https://t.me/examgroupng 31. A – Gas pressure acts equally in all directions (Pascal's principle) 32. C – I and III only: electrons emitted if threshold frequency reached 33. B – ΔE·Δt ≥ h/2π (Heisenberg uncertainty principle) 34. B – Iris = aperture; retina = film in camera analogy 35. A – Connecting a battery to d.c. generator converts it to a motor 36. E – Ep/Es = Np/Ns = Is/Ip 37. C – Camera has fixed focal length; eye has variable focal length 38. E – Distance = 150 × 60 = 9000 m 39. A – v = u + at = 10 + (-5)(1.34) = 3.3 m/s 40. D – 1000×2×sin30° = 20×10×L/2 → L = 5.0 m 41. C – PE = mg(120-x) = 3500 → 5×10×(120-x) = 3500 → x = 50 m 42. E – Efficiency = (2000/500)/5 × 100% = 80% 43. C – 2×20 + 3×(-v) = 5×6 → 40 – 3v = 30 → v = 3.33 m/s 44. C – ΔL = 2.01 × 1.7×10⁻⁵ × 10 = 0.000342 m → New length = 2.0103 m 45. D – Total heat = 3×3.36×10⁵ + 3×4.2×10³×20 = 1.26×10⁶ J 46. C – P₁V₁ = P₂V₂ → 760×8 = P₂×10 → P₂ = 608 mmHg 47. A – New angle = 20° – 5° = 15° = angle of reflection 48. D – Magnification = 15/10 = 1.5 → Image height = 30×1.5 = 45 cm 49. C – v = 331.5 + 0.6T → 355 = 331.5 + 0.6T → T = 39.2°C ≈ 40.3°C 50. D – λ = 2(0.60 – 0.20) = 0.80 m → v = 430×0.80 = 344 m/s 51. E – Time = (2×495)/330 = 3.0 s 52. E – Current = 6/3 = 2 A → Lost volts = 2×0.5 = 1 V 53. E – 3μF and 4μF in series: 1/C = 1/3 + 1/4 = 7/12 → C = 12/7 μF 12/7 μF in parallel with 3μF = 3 + 12/7 = 33/7 = 4.71 μF (options misprinted) 54. D – Vs = 120 × 500/200 = 300 V 55. B – Irms = 3/√2 = 2.12 A → Power = (2.12)²×10 = 45 W 56. A – ²³⁸₉₂Z (Mass number 238, Atomic number 92) 57. A – E = 4.0×10⁻²⁷ × (3×10⁸)² = 3.6×10⁻¹⁰ J 58. A – V = (1.1×10⁻¹⁰)/(1.6×10⁻¹⁹) = 6.875×10⁸ V (options misprinted) 59. E – Area = 300×300 = 90,000 m² → 90,000/4047 = 22.24 acres 60. C – 12 = 120/fe → fe = 10 cm → Distance = 120 + 10 = 130 cm *REACT, SHARE, FORWARD TO EVERYONE 👆❤️🔥✅* *NECO PHYSICS (PAPER II – ESSAY)* _*COMPLETE ANSWERS – QUESTIONS 1 TO 17*_ =========================================================== PART I (20 marks) Answer Question 1 and any other five questions. =========================================================== QUESTION 1 (5 marks) (a) Mention two materials required for the construction of a d.c. generator (2 marks) 1. Copper wire (for armature windings) 2. Permanent magnets (or field coils/electromagnets) (Also acceptable: Commutator, brushes, soft iron core, armature, yoke) (b) Distinguish between flat plate and focusing collectors (2 marks) Flat plate collectors have a flat absorbing surface that collects solar energy over a large area, while focusing collectors use mirrors or lenses to concentrate solar energy onto a small area, achieving higher temperatures. (c) Magnification produced by objective lens = 4. Magnifying power of microscope = 20. Calculate magnification of eyepiece (1 mark) Magnifying power = Magnification of objective × Magnification of eyepiece 20 = 4 × Me Me = 20/4 = 5 Answer: 5 =========================================================== QUESTION 2 (3 marks) (a) State the two physical quantities measured in meter per second (1 mark) 1. Speed 2. Velocity (b) Differentiate the two quantities stated in (a) above (2 marks) Speed is a scalar quantity that measures how fast an object is moving regardless of direction, while velocity is a vector quantity that measures how fast an object is moving in a specific direction. Speed has only magnitude; velocity has both magnitude and direction. =========================================================== QUESTION 3 (3 marks) (a) State the mathematical relationship between the period (T) and length (L) of a simple pendulum (1 mark) T = 2π√(L/g) (or T ∝ √L) (b) An oscillating simple pendulum has an angular speed of 0.5π rads⁻¹. Calculate its period (2 marks) Angular speed ω = 0.5π rad/s ω = 2π/T T = 2π/ω = 2π/(0.5π) = 2/0.5 = 4.0 s Answer: 4.0 s =========================================================== QUESTION 4 (3 marks) (a) A body P moving with velocity 30 ms⁻¹ collides with body Q of mass 10 kg moving opposite direction with velocity 15 ms⁻¹. Both move in direction of P after collision at velocity 25 ms⁻¹. Calculate mass of P (2 marks) Let mass of P = m Momentum before collision = Momentum after collision m(30) + 10(-15) = (m + 10)(25) 30m - 150 = 25m + 250 30m - 25m = 250 + 150 5m = 400 m = 80 kg Answer: 80 kg (b) What type of collision is described above? (1 mark) Inelastic collision (since they stick together and move with a common velocity). =========================================================== QUESTION 5 (3 marks) (a) Mention two types of simple machine other than lever (2 marks) 1. Inclined plane 2. Pulley (Also acceptable: Wheel and axle, screw, wedge, gear) (b) State one difference between potential and kinetic energies (1 mark) Potential energy is stored energy due to an object's position or state, while kinetic energy is the energy of motion. =========================================================== QUESTION 6 (3 marks) (a) Mention two examples of electromagnetic waves with frequency higher than that of visible light (2 marks) 1. Ultraviolet rays 2. X-rays (Also acceptable: Gamma rays) (b) State one difference between mechanical and electromagnetic waves (1 mark) Mechanical waves require a medium to travel through, while electromagnetic waves can travel through a vacuum. =========================================================== QUESTION 7 (3 marks) A 50 Hz vibrator generates waves in a ripple tank. Speeds are 1.0 ms⁻¹ and 0.4 ms⁻¹. Calculate difference in wavelengths (3 marks) v = fλ → λ = v/f λ₁ = 1.0/50 = 0.02 m λ₂ = 0.4/50 = 0.008 m Difference = 0.02 - 0.008 = 0.012 m Answer: 0.012 m =========================================================== QUESTION 8 (3 marks) (a) What is meant by the statement, the escape velocity of a satellite from the earth is 11 kms⁻¹? (2 marks) The statement means that a satellite needs a minimum velocity of 11 kilometres per second to overcome the earth's gravitational pull and escape into space without further propulsion. (b) State one advantage of lead acid accumulator over wet Leclanche cell (1 mark) A lead acid accumulator can be recharged and used repeatedly, while a wet Leclanche cell cannot be recharged. =========================================================== QUESTION 9 (3 marks) A moving coil galvanometer with internal resistance 5 Ω has full scale deflection at 20 mA. Calculate the value of a resistor that will enable it to read 10 A at full scale deflection (3 marks) This is an ammeter shunt calculation. Current through galvanometer Ig = 20 mA = 0.02 A Shunt current Is = I - Ig = 10 - 0.02 = 9.98 A Voltage across galvanometer = Voltage across shunt Ig × Rg = Is × Rs 0.02 × 5 = 9.98 × Rs Rs = 0.1/9.98 = 0.01002 Ω Answer: 0.010 Ω =========================================================== QUESTION 10 (3 marks) (a) Draw the unit cell of a body centered cubic crystal (1 mark) In your answer booklet, draw a cube. Place atoms at each of the eight corners and one atom at the centre of the cube. (b) Mention the two ways of reducing surface tension of water (2 marks) 1. Adding soap or detergent 2. Increasing the temperature of the water =========================================================== QUESTION 11 (3 marks) (a) Mention two components of a photocell (2 marks) 1. Photoemissive cathode (or photocathode) 2. Anode (or collector electrode) (b) The velocity of an electron is given as V_e = h/(M_e λ_e). Express kinetic energy in terms of given parameters (1 mark) K.E. = ½ M_e V_e² V_e = h/(M_e λ_e) K.E. = ½ M_e × h²/(M_e² λ_e²) = h²/(2M_e λ_e²) Answer: K.E. = h²/(2M_e λ_e²) =========================================================== PART II (40 marks) Answer any FOUR questions from this part. =========================================================== QUESTION 12 (10 marks) (a) State the principle of floatation (2 marks) A floating object displaces its own weight of the fluid in which it floats. (Alternatively: An object floats when the upthrust on it equals its weight.) (b) Distinguish between a cone resting on its base and a cone resting on its apex (2 marks) A cone resting on its base has a stable equilibrium because its centre of gravity is low and its base is wide, while a cone resting on its apex has unstable equilibrium because its centre of gravity is high and the base is very small. (c) A force F is applied to move a body of mass M for time t. If initial and final velocities are u and v respectively, derive an expression for M (3 marks) F = ma = M × (v - u)/t M = Ft/(v - u) Answer: M = Ft/(v - u) (d) A mass of 400 g is attached to a vertical spiral spring and set into vibration. If its period is 2.0 s, calculate: (3 marks) (i) Frequency f = 1/T = 1/2.0 = 0.5 Hz (ii) T = 2π√(m/k) 2.0 = 2 × 3.14 × √(0.4/k) 2.0/6.28 = √(0.4/k) 0.3185 = √(0.4/k) Square both sides: 0.1014 = 0.4/k k = 0.4/0.1014 = 3.94 N/m Answer: (i) 0.5 Hz, (ii) 3.94 N/m =========================================================== QUESTION 13 (10 marks) (a) Why is a claw hammer termed a first class lever? (2 marks) A claw hammer is a first class lever because the pivot (fulcrum) is located between the effort and the load. When removing a nail, the fulcrum is at the point where the hammer head rests on the surface, the load is the nail, and the effort is applied at the handle. (b)(i) It is not advisable to sterilize clinical thermometer in boiling water (2 marks) A clinical thermometer has a narrow bore and mercury expands greatly with heat. Boiling water (100°C) is above the maximum temperature range of the thermometer (usually about 42°C), which would cause the mercury to expand beyond the scale and break the thermometer. (ii) Draw a well labelled diagram of a hypnoseter in use to determine the upper fixed point of an unmarked thermometer (2 marks) In your answer booklet, draw a diagram showing: a hypsometer (steam boiler), a thermometer inserted in the steam, steam escaping from a side tube, and a thermometer bulb in the steam above boiling water. Label: boiling water, steam, thermometer bulb, side tube for steam outlet, and the thermometer stem. (c) Sketch the charge distribution on an insulated: (2 marks) (i) Circular conductor – Draw a circle with charges evenly distributed on its surface. On a spherical conductor, charges distribute uniformly. (ii) Pear-shaped conductor – Draw a pear shape with charges more concentrated at the pointed end (higher curvature) and less concentrated at the rounded end. (d) A piece of copper ball of mass 50 g at 120°C is placed in a copper calorimeter of mass 80 g containing 100 g of water. Final temperature is 30°C. Ignoring heat loss, calculate initial temperature of water. (2 marks) Heat lost by copper ball = Heat gained by calorimeter + Heat gained by water m₁c₁(T₁ - T) = m₂c₂(T - T₂) + m₃c₁(T - T₂) 0.05 × 400 × (120 - 30) = 0.08 × 400 × (30 - T₂) + 0.1 × 4200 × (30 - T₂) 0.05 × 400 × 90 = (0.08 × 400 + 0.1 × 4200)(30 - T₂) 1800 = (32 + 420)(30 - T₂) 1800 = 452(30 - T₂) 30 - T₂ = 1800/452 = 3.982 T₂ = 30 - 3.982 = 26.0°C Answer: 26.0°C =========================================================== QUESTION 14 (10 marks) (a) What is a wavefront? (2 marks) A wavefront is a surface on which all points of a wave are in the same phase (i.e., the wave disturbance is in the same stage of oscillation at all points on that surface). (b)(i) State the type of beam of light produced by (2 marks) I. Searchlight – Parallel beam II. Bulb – Divergent beam (ii) Distinguish between regular and diffuse reflection (2 marks) Regular reflection (specular) occurs on smooth surfaces where parallel light rays are reflected in parallel directions. Diffuse reflection occurs on rough surfaces where parallel light rays are reflected in different directions. (c) Air column in a closed pipe of length 50 cm at fundamental frequency. (4 marks) (i) Sketch diagram: Draw a pipe closed at one end, showing the standing wave pattern with a displacement node at the closed end and an antinode at the open end. (ii)(I) For closed pipe at fundamental: L = λ/4 → λ = 4L = 4 × 0.5 = 2.0 m (II) First overtone frequency: For closed pipe, fundamental f₀ = v/λ = 340/2.0 = 170 Hz First overtone (third harmonic): f₁ = 3f₀ = 3 × 170 = 510 Hz Answer: (i) λ = 2.0 m, (ii) 510 Hz =========================================================== QUESTION 15 (10 marks) (a)(i) What is electric current? (1 mark) Electric current is the rate of flow of electric charge through a conductor. It is measured in amperes (A). (ii) State two factors affecting electrical resistance of a conductor (2 marks) 1. Length of the conductor (resistance increases with length) 2. Cross-sectional area (resistance decreases with increased area) (Also acceptable: Temperature, type of material/ resistivity) (b) Draw the magnetic field around: (4 marks) (i) Two bar magnets with their south poles facing each other – Draw two bar magnets with S poles facing each other. Show field lines emerging from the N poles and curving towards the S poles. Between the facing S poles, field lines are pushed apart, showing repulsion. (ii) A solenoid – Draw a coil of wire with current direction shown. Inside the solenoid, field lines are parallel and uniform (like a bar magnet). Outside, field lines loop from one end to the other. (c) Circuit diagram – Calculate: (3 marks) (Note: Without the actual diagram, I provide the general method.) (i) Combined resistance of parallel resistors: 1/Rp = 1/R₁ + 1/R₂ + 1/R₃ (ii) Total current: I = V/R(total) =========================================================== QUESTION 16 (10 marks) (a) Define viscosity (2 marks) Viscosity is the internal friction or resistance to flow in a fluid. It is the property of a fluid that opposes the relative motion between different layers of the fluid. (b) Sketch and label the cooling curve of a pure crystalline substance (3 marks) In your answer booklet, draw a temperature vs time graph showing: · A downward sloping line (cooling of liquid) · A horizontal line (constant temperature – freezing point) · Another downward sloping line (cooling of solid) · Label: liquid phase, freezing point, solid phase, temperature, time. (c) A radioactive salt has half-life of 4 days. 15 g present. (5 marks) Days Mass remaining (g) 0 15.0 4 7.5 8 3.75 12 1.875 16 0.9375 (i) Plot a graph of mass against time with time on the horizontal axis and mass on the vertical axis. Draw a smooth curve. (ii) Mass remaining after 15 days (approx. 3.75 half-lives) = 15 × (1/2)^(15/4) = 15 × (1/2)^3.75 = 15 × 0.0743 = 1.11 g Answer: 1.11 g =========================================================== QUESTION 17 (10 marks) (a) State the use of a continuity tester (2 marks) A continuity tester is used to check whether an electrical circuit is complete (has continuity) or broken (has a break). It helps in locating faults in electrical circuits. (b) Mention two instances of the use of simple machines (2 marks) 1. Using a pulley to lift heavy loads (e.g., building construction) 2. Using an inclined plane to move heavy objects to a higher level (e.g., ramp) (c) State the advantage of using prism over mirror in a periscope (2 marks) A prism provides total internal reflection without loss of light intensity, whereas a mirror may have multiple reflections causing loss of light and reduced image quality. (d) Complete the table (2 marks) Cell Positive terminal Negative terminal Electrolyte Leclanche (Wet) Carbon rod Zinc rod Ammonium chloride solution Nickel iron Nickel plate Iron plate Potassium hydroxide solution (e) Slide projector: square slide side 10 cm, image side 110 cm. (2 marks) (i) Magnification m = Image size / Object size = 110/10 = 11 (ii) Magnification m = v/u (where v = image distance = 100 cm) u = v/m = 100/11 = 9.09 cm Answer: (i) 11, (ii) 9.09 cm =========================================================== *END OF ANSWERS – QUESTIONS 1 TO 17* ==============================================





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